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tiny-mole [99]
3 years ago
15

The penny size of a nail indicates the length of the nail. The penny size d is given by the literal equation d=4n−2, where n is

the length (in inches) of the nail. a. Solve the equation for n. n= Question 2 b. Use the equation from part (a) to find the lengths of nails with the following penny sizes: 3, 6, and 10. A 3-penny nail is inches. A 6-penny nail is inches. A 10-penny nail is inches.
Mathematics
2 answers:
sleet_krkn [62]3 years ago
6 0
D=4n-2, d+2=4n-2+2, d+2=4n
(d+2)/4=(4n)/4, 1/4d+1/2=n
n=1/4n+1/2

size 3=
n=1/4*3/1=3/4, 3/4+1/2=5/4=1 1/4
size 3=1 1/4

size 6=
n=1/4*6/1=6/4, 6/4+1/2=8/4=2
size 6=2

size 10=
n=1/4*10/1=10/4, 10/4+1/2=12/4=3
size 10=3
LekaFEV [45]3 years ago
5 0

Answer:

The penny size d is given by the literal equation d=4n-2

Where n is the length (in inches) of the nail.

We can deduce the value of n from equation above:

(d+2)/4=n

Now we have to find n with various values of d.

1. when d = 3 inches

n=(3+2)/4

=>n=5/4

n = 1.25 inches

2. when d = 6 inches

n=(6+2)/4

=>n=8/4

n = 2 inches

3. when d = 10 inches

n=(10+2)/4

=>n=12/4

n = 3 inches

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3. Tom, Sam and Matt are counting drum beats.
just olya [345]

Answer:

<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>

Step-by-step explanation:

The Least Common Multiple ( LCM )

The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.

For example:

LCM(20,8)=40

LCM(35,18)=630

Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.

Find the LCM of 4,10,12. Follow this procedure:

List prime factorization of all the numbers:

4 = 2*2

10 = 2*5

12 = 2*2*3

Multiply all the factors the greatest times they occur:

LCM=2*2*3*5=60

Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.

6 0
3 years ago
What is the integer closest to the square root of 17
Alex Ar [27]

Answer:

4

Step-by-step explanation:

\sqrt{16} = 4

7 0
3 years ago
Read 2 more answers
Convert 2FA.C8 base 16. express in Octal form, Quinary or pental form and Binary form​
Sunny_sXe [5.5K]

Using base conversion method, 2FA.C8 base 16 can be expressed as:

  • 1372.628 in octal
  • 11022.3423120034 in pental
  • 1011111010.11001 in binary

<h3>What is 2FA.C8 base 16 expressed in Octal form?</h3>

To express 2FA.C8 in octal form, it is first converted to a decimal form as follows:

where:

F = 15

A = 10

C = 12

2FA.C8 = 2 × 16^2 + F × 16^1 + A × 16^0 + C × 16^-1 + 8 × 16^-2

2FA.C8 = 762.7812510 in decimal.

Then, convert 762.7812510 to octal as follows:

  • First the integral part is converted to octal by repeated division by 8.
  • The fractional part is converted to octal by repeated multiplication by 8 until we get to zero (here, we calculate up to ten digits)
  • add the integral and fractional part together

762 / 8 = 95 remainder 2

95 / 8 = 11 remainder 7

11 / 8 = 1 remainder 3

1 / 8 = 0 remainder 1

762 = 1372

Then;

0.78125 × 8 = 6 + 0.25

0.25 × 8 = 2 + 0

0.78125 = 0.62

Therefore, 762.78125 in decimal = 1372.628 in octal

<h3>What is 2FA.C8 base 16 expressed in pental form?</h3>

To convert 2FA.C8 base 16 to pental form, we use its value in decimal for conversion.

  • 2FA.C8 base 16 = 762.7812510 base 10

Then, convert 762.7812510 to pental as follows:

  • First the integral part is converted to pental by repeated division by 5
  • The fractional part is converted to pental by repeated multiplication by 5 until we get to zero (here, we calculate up to ten digits)
  • add the integral and fractional part together

762 / 5 = 152 remainder 2

152 / 5 = 30 remainder 2

30 / 5 = 6 remainder 0

6 / 5 = 1 remainder 1

1 / 5 = 0 remainder 1

  • 762 in decimal = 11022 in pental

Then 0.78125 to pental:

0.78125 × 5 = 3 + 0.90625

0.90625 × 5 = 4 + 0.53125

0.53125 × 5 = 2 + 0.65625

0.65625 × 5 = 3 + 0.28125

0.28125 × 5 = 1 + 0.40625

0.40625 × 5 = 2 + 0.03125

0.03125 × 5 = 0 + 0.15625

0.15625 × 5 = 0 + 0.78125

0.78125 × 5 = 3 + 0.90625

0.90625 × 5 = 4 + 0.53125

Thus, 0.78125 in decimal = 0.3423120034 in pental

Therefore, 762.78125 in decimal = 11022.3423120034 in pental.

<h3>What is 2FA.C8 base 16 expressed in Binary form?</h3>

To convert 2FA.C8 base 16 to binary form, we use its value in decimal for conversion.

  • 2FA.C8 base 16 = 762.7812510 base 10

Then, convert 762.7812510 to binary as follows:

  • First the integral part is converted to binary by repeated division by 2
  • The fractional part is converted to binary by repeated multiplication by 2 until we get to zero (here, we calculate up to ten digits)
  • add the integral and fractional part together

762 / 2 = 381 remainder 0

381 / 2 = 190 remainder 1

190 / 2 = 95 remainder 0

95 / 2 = 47 remainder 1

47 / 2 = 23 remainder 1

23 / 2 = 11 remainder 1

11 / 2 = 5 remainder 1

5 / 2 = 2 remainder 1

2 / 2 = 1 remainder 0

1 / 2 = 0 remainder 1

  • 762 base 10 = 1011111010 base two

Then 0.78125 to binary:

0.78125 × 2 = 1 + 0.5625

0.5625 × 2 = 1 + 0.125

0.125 × 2 = 0 + 0.25

0.25 × 2 = 0 + 0.5

0.5 × 2 = 1 + 0

0.78125 base 10 = 0.11001 base two

Therefore, 762.78125 base 10 = 1011111010.11001 base two.

Learn more about base conversion at: brainly.com/question/17946394

4 0
2 years ago
If 1/2 is multiplied by 1/2, will the product be greater than 1/2? Explain​
lakkis [162]
No the product will not be greater then one half if you multiply those two fractions your will get 1/4 there for your answer will not be greater

Answer is 1/4
7 0
3 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
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