I rushed to the door to see what loud noise i heard, I seen a strange man standing on top of a body. As I screamed loudly, he started rushing towards me. ... He then began to slice my neck and I started to bleed out and collapsed on my front door. I suddenly woke up and realized it was all a dream, I went back to sleep.
State the periodic law and explain how it relates to the periodic table.
Seafloor spreading and rifts hopefully that helpful
The mass of the ethylene glycol used is 14.26 g
<h3>What is the freezing point?</h3>
The freezing point is the temperature at which a liquid is converted to a solid.
Given that;
ΔT = 0.0°C - ( -4.3°C) = 4.3°C
ΔT = 4.3°C
But we know that
ΔT = k m i
m = ΔT/k i
m = 4.3°C/1.86 °C/m * 1
m = 2.3 m
Now;
Let the mass of ethylene glycol be m
Molar mass of ethylene glycol = 62 g/mol
Mass of solvent = 100.0 g or 0.1 Kg
Then;
2.3= m/62/0.1
2.3 = m/62 * 0.1
m = 2.3 * 62 * 0.1
m = 14.26 g
Learn more about freezing point:brainly.com/question/3121416?
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Answer:
There will be 525.2 grams of K3N produced
Explanation:
Step 1: Data given
Number of moles of potassium oxide ( K2O) = 6 moles
Magnesium nitride (Mg3N) = in excess
Molar mass of K3N = 131.3 g/mol
Step 2: The balanced equation
Mg3N2 + 3K2O → 3MgO + 2K3N
Step 3: Calculate moles of K3N
The limiting reactant is K2O.
For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N
For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N
Step 4: Calculate mass of K3N
Mass of K3N = moles K3N * molar mass K3N
Mass of K3N = 4 moles * 131.3 g/mol
Mass of K3N = 525.2 grams
There will be 525.2 grams of K3N produced