Answer:
40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.
Step-by-step explanation:
Since a chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture, and the premium antifreeze solution contains 70% pure antifreeze, and the company wants to obtain 140 gallons of a mixture that contains 20% pure antifreeze, to To determine how many gallons of water and how many gallons of the premium antifreeze solution must be mixed, the following calculation must be performed:
50 x 0.7 + 50 x 0 = 35
40 x 0.7 + 60 x 0 = 28
30 x 0.7 + 70 x 0 = 21
29 x 0.7 + 71 x 0 = 20.3
28.57 x 0.7 + 71.43 x 0 = 20
140 x 0.2857 = 40
Therefore, 40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.
Answer:
essentially the answer is 33
now, with that template in mind, let's check this one
A = -1, reflection over the x-axis.
B = 1, C = +3, C/B = +3/1 = +3, horizontal shift to the left of 3 units.
D = 5, vertical shift up of 5 units.
10,080 because you can multiply it out....
