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Alekssandra [29.7K]
3 years ago
10

Susan, Hong, and Juan sent a total of 107 text messages over their cell phones during the weekend. Hong sent 4 times as many mes

sages as Juan. Juan sent 5 fewer messages than Susan. How many messages did they each send?
Mathematics
2 answers:
scoray [572]3 years ago
6 0
X: Nb of Susan’s texts

4(x-5)+(x-5)+x= 107
Isolate X
X=107

Replace X with 22 in each equation to find out the number of texts

Susan: 22 Texts ( x )
Hong: 68 Texts 4( x-5 )
Juan: 17 Texts ( x-5 )
adell [148]3 years ago
3 0

Answer: susan sent 22 texts

Hong sent 68 texts

Juan sent 17 texts

Step-by-step explanation:

Let x represent the number of text messages that Susan sent during the weekend.

Let y represent the number of text messages that Hong sent during the weekend.

Let z represent the number of text messages that Juan sent during the weekend.

Susan, Hong, and Juan sent a total of 107 text messages over their cell phones during the weekend. This means that

x + y + z = 107 - - - - - - - - 1

Hong sent 4 times as many messages as Juan. This means that

y = 4z

Juan sent 5 fewer messages than Susan. This means that

x = z + 5

Substituting y = 4z and x = z + 5 into equation 1, it becomes

z + 5 + 4z + z = 107

z + 4z + z = 107 - 5

6z= 102

z = 102/6 = 17

x = z + 5 = 17 + 5 = 22

y = 4z = 17×4 = 68

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<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

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Explanation for Q.A.:

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