If you have a graph, I’d use it and make curved lines going down to plot the points!
Using -17 ,15
And, 15 , -13
Hope this helps!
Answer:
D is the answer
Step-by-step explanation:
For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.
For b: Both functions do have all real numbers for their domain, b is true
For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true
For d: g(3) = 7, f(3) = 3^2 - 2(3) + 2 = 5, d is false.
Y -:5 = 2/3x + 6 because 6 is 2/3 of 9
add 5 to both sides
y - 5 +:5 = 2/3x + 6 + 5
y = 2/3x + 11
the y intersept is 11 or (0 , 11) when x is 0
when x is 3
y = 2/3 (3) + 11 or 2 + 11 = 13
so a 2nd point could be (3 , 13)
Answer:
45
Step-by-step explanation:
15 x 3 = 45 - 3 = 42
