F(x)=2x/(x-1)
Denominator cannot be equal 0.
x-1=0
x=1 is vertical asymptote.
To find horizontal asymptote
we need divide the coefficients before x
y=2x/x=2,because when x becomes really big (x---->∞) , value of 1 will not influence the result .
y=2 is horizontal asymptote
The first choice. -3 is the party to the left of the vertical all line. 2 is the part to the right. that segment is 5 units long
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
A = w*l
5/8 = w*10
w = (5/8)/10 = (5/8)*(1/10) = 5/80 = 1/16
w=1/16
