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aniked [119]
3 years ago
8

Write an equation in point-slope form of the line that passes through

Mathematics
2 answers:
zhenek [66]3 years ago
6 0
This one was though, but I think it might be y= -1/12x - 53/12.

Hope I helped!
Crazy boy [7]3 years ago
4 0
Point slope format is represented as this
y-y1=m(x-x1)
So the answer would be
y-(-4)= -1/12(x-(-5))
Then you can simplify it by getting rid of the negative signs
y+4= -1/12(x+5)
that would be the correct answer.
And you can use either one of the points to plug into the equation I used (-5,-4) as you can see
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2(m⁴ - 9n⁶)
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2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
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6 0
3 years ago
What would my final balance be if i put $650 in the bank for 60 months with an interest rate of 6%?
Flauer [41]
Your final balance would be $2,340.

I = Prt
Percent (6%) x rate (650) x time (60 months) = 2,340

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0.06 x 60 x 650 = 2,340


3 0
3 years ago
Can someone please help me Factor 4x^2 - 81
Vsevolod [243]

Answer:

(2x-9)(2x+9)

Step-by-step explanation:

This is a difference of squares because it can be written as (2x)^2-9^2

The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)

So replace a with 2x and b with 9 giving us

4x^2-81=(2x-9)(2x+9)

3 0
3 years ago
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makkiz [27]
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6 0
3 years ago
Read 2 more answers
write the equation of a line that is perpendicular to the given line and that passes through the given point. y-4=5/2(x+3) ; (-7
faltersainse [42]
The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.

The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
7 0
3 years ago
Read 2 more answers
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