Ask question

Ask question

All categories

3 years ago

10

Jude is placing boxes on a shelf that holds no more than 80 lb. He has x small boxes that weigh 5 lb each and y large boxes that

weigh 12 lb each. Jude needs at least 4 small boxes on the shelf. Which inequalities model the situation? Choose exactly two answers that are correct.
it was a and d btw for future helping
Choose exactly two answers that are correct. Question 12 options:5x + 12y ≤ 805x + 12y < 80x > 4 and y > 0x ≥ 4 and y ≥ 0

1 answer:

Rashid [163]3 years ago

5 0

The term "no more than" implies "less than or equal to" in an equality.
Therefore, the inequality is:
5x + 12y ≤ 80
Given that he wants at least 4 small boxes on the shelf, x ≥ 4
so x ≥ 4 and y ≥ 0

You might be interested in

Find the rate of change for this linear function Y equals MX plus be

Crazy boy [7]

Y=mx+b is an equation

8 0

4 years ago

__________ reasoning is a type of reasoning that uses previously proven or accepted properties to reach conclusions.

Alekssandra [29.7K]

Deductive reasoning is your answer

5 0

3 years ago

If a famer plows 2 acres every 3 hours how long will it take to plow 60 acres

Elina [12.6K]

it take him 90 hrs to plow 60 acres

4 0

3 years ago

One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the

Kipish [7]

Let's call the two numbers $s$ and $l$ .

Given these variables, we can say: $s = l - 14$ , based on the first sentence in the problem.

Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

$\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}$

To solve, we can simply substitute $l -14$ in for $s$ in the second equation and solve.

$\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}$

Set up

$\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}$

Get terms on the left side to a common denominator for easier addition

$\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}$

Simplify

$4(6l - 70) = l(l - 14)$

Cross multiplication ( $\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc$ )

$24l - 280 = l^2 - 14l$

Simplify

$l^2 - 38l + 280 = 0$

Subtract $24l - 280$ from both sides of the equation

$(l - 10)(l - 28) = 0$

Factor left side of the equation

$l = 10, 28$

Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

$s = 10 - 14 = -4$ ,

Since $s$ is not positive in this case, $l = 10$ is not a solution.

Thus, $l = 28$ is our only solution. In this case,

$s = 28 - 14 = 14$ ,

which means that the smaller number is 14 and the larger number is 28.

5 0

3 years ago

The price of an item yesterday was $60. Today, the price fell to $42. Find the percentage decrease.

oksian1 [2.3K]

Answer:

-30% or 30% decrease

Step-by-step explanation:

What's percentage decrease?

Percent decrease is the difference between the initial value and new value, indicating a loss of value.
The formula to find percent decrease is $\frac{NV-IV}{IV} * 100$ , where NV = new value and IV = initial value.

How do we solve this problem?

We know that the original value was $60, so that represents IV. Also, now that the price is $42, it represents NV.
Now, we plug in the values!
$\frac{42-60}{60} * 100$
$\frac{-18}{60} * 100$
$-\frac{3}{10} * 100$
$-3 * 10$
$-30$

Therefore, the answer is 30% decrease.

6 0

2 years ago