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kari74 [83]
3 years ago
5

A number is no less than 13

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer: yes a number is less than 13

Step-by-step explanation:

3241004551 [841]3 years ago
6 0
Yes a number is no less than the number 14
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The first answer is factual, but please help.
DIA [1.3K]

Answer:

B) 2

C) y = 2x

Step-by-step explanation:

Part B

Constant is 2 because in order to get x to the value of y, you must multiply by 2.

Part C

y = 2x

3 0
2 years ago
Megan's cousin wants to buy a new sound system for his car. She goes to the electronics store to help him to pick it out. The ba
Nikitich [7]

Answer:D


Step-by-step explanation:


5 0
3 years ago
Identify the reference angle ∅ for each given angle, 0.
frutty [35]

Answer:

When Ø = 300°, Ø = 60 degrees.

When Ø = 225°, Ø = 45 degrees.

When Ø = 480°, Ø = 60 degrees.

When Ø = -210°, Ø = 30 degrees.

Step-by-step explanation:

Reference angles are in Quadrant I (0° to 90°).

1. Find 300° (Quadrant IV) on the unit circle. Since it's in Quadrant IV, you use 360 - 300 = 60° to get your answer.

2. Find 225° (Quadrant III) on the unit circle. Since it's in Quadrant III, you use 225 - 180 = 45° to get your answer.

3. The angle 480° is not on the unit circle. To find its corresponding angle between 0° and 360°, use 480 - 360 = 120°. Then, find 120° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 120 = 60° to get your answer.

4. The angle -210° is not on the unit circle. To find its corresponding angle between 0° and 360°, use -210 + 360 = 150°. Then, find 150° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 150 = 30° to get your answer.

5 0
3 years ago
A gravel path is to be built around an 18‘ x 15‘ rectangle garden if the width remains constant how why can the path be if there
Ilia_Sergeevich [38]

Answer:

P = 2*(18 + 13) = 62ft

Now to figure out the width of the path we have to do some geometry. There are 3 basic shapes we will use for the path, they are the 13 ft long rectangle, the 18 ft long rectangle, and the squares formed at the corners. These squares' areas are equal to the width squared, whereas the rectangles are only equal to the length times the width. Our total area then becomes:

A = 2*(13*w) + 2*(18*w) + 4*(w*w)

A = 4w^2 + 62w

And since we know the available area is 516 ft^2, putting this in for A and solving the quadratic equation we can get the width:

516 = 4w^2 + 62w

0 = 4w^2 + 62w - 516

Using the quadratic formula: (w = -b2+/-SQRT(b^2 - 4ac)/2a, where a = 4, b = 62, and c = -516)

w = 6, -21.5

Since we obviously cannot have a negative width, 6 must be our answer. Therefore the path can be 6 feet wide!

We can check this answer by doing the following. Please note that by having a 6ft wide path you would actually be adding 12 ft to both dimensions, since you add 6 feet of length to both sides. Your total area would then become:

18+(2*6) x 13+(2*6) = 30x25 = 750 ft^2

Subtracting the area of the garden gives you the are of the gravel required:

750ft^2 - (18*13)ft^2 = 516ft^2

Therefore a width of 6 feet is correct.

Step-by-step explanation:

6 0
3 years ago
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How do you get the constant rate of proportionallity in a chart
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You have to add all the quantities and then dived between the numbers of amounts
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3 years ago
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