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topjm [15]
3 years ago
10

Graph y−5=43(x−5) help quick

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer:

use desmos

Step-by-step explanation:

Jobisdone [24]3 years ago
3 0

Answer:

y=43x -210

Step-by-step explanation:

distibute and simplify

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Which of these terms is unlike the others?<br> 4b, b, 4, 7b <br> A. 4b<br> B. b<br> C. 4<br> D. 7b
olga_2 [115]

Answer:

C. 4

Step-by-step explanation:

All other answer choices involve the variable 'b' and/or are tied to it in some way. The sole number 4 has no connection to the variable b, therefore it is C. 4.

5 0
3 years ago
At PRMS, 25% of the 124 students Mrs. Pasternak teaches buy their lunches in the cafeteria. How many students buy their lunches
Ksju [112]
25% = 0.25
124 x 0.25 = 31

31 students bought their lunch.

Part = 31
Percent = 25%
Whole = 124

Hope this helps! ✨
6 0
3 years ago
Find the area of the polygon. 32 m 20 m 16 m 40 m he area of the polygon is square meters.​
jenyasd209 [6]

Answer:

Step-by-step explanation:

4 0
2 years ago
What are the domain and range of the exponential function below? <br><br> <img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%205%5
faust18 [17]

Answer:

B

Step-by-step explanation:

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Attached is the graph of the exponential function.

It is the basic graph of exponential function of y = 5^x which is shifted 6 units above (because of +6 at the end).

<em><u>Looking at the graph, the domain is the set of all x values.</u></em>

<em><u>The range is anything above 6.</u></em>

Correct answer is B.

3 0
2 years ago
A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of
ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

          it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

7 0
2 years ago
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