Can someone please check to see if I selected the right answer... Please

Explain how to write and solve an equation to find an unknown side length of a rectangle when given the perimeter

ratelena [41]

P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L

4 0

3 years ago

A 4-column table with 5 rows. The first column is labeled age (years) with entries 1, 2, 3, 4, 5. The second column is labeled g

sweet [91]

Answer:

any other info?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

8 divided by 6.403 round to the nearest tenths

lions [1.4K]

I believe the answer is 1.2

6 0

3 years ago

Read 2 more answers

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

Question

AlekseyPX

Answer:

The population mean is 5 volts

Step-by-step explanation:

Output voltage is assumed to be normally distributed, with standard deviation 0.25 Volts

s=0.25

n = 8

$H_0:\mu = 5\\H_a:\mu \neq 5$

Sample mean = $\bar{x}=4.85$

Since n < 30 and population standard deviation is unknown

So, we will use t test

Formula : $t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{4.85-5}{\frac{0.25}{\sqrt{8}}}$

t=-1.69

Refer the t table for p value

Degree of freedom = n-1 = 8-1 = 7

So, $t_{(df,\alpha)}=t_{7,0.05}=2.365$

P value >α

So, We are failed to reject null hypothesis

Hence The population mean is 5 volts

7 0

3 years ago

Can someone please check to see if I selected the right answer... Please ​

Can someone please check to see if I selected the right answer... Please