the answer for the second problem is x=99 degrees and y= 261 degrees
dunno the first problem :/
<h3>
Answer: Vertex is (2,2)</h3>
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Explanation:
The equation
y = -3x^2 + 12x - 10
is in the form
y = ax^2 + bx + c
with a = -3, b = 12, c = -10
Plug the 'a' and 'b' values into the equation below to find the x coordinate of the vertex
h = -b/(2a)
h = -12/(2*(-3))
h = -12/(-6)
h = 2
The x coordinate of the vertex is h = 2, which is then used to find the y coordinate of the vertex
y = -3x^2 + 12x - 10
y = -3(2)^2 + 12(2) - 10
y = -3(4) + 12(2) - 10
y = -12 + 24 - 10
y = 12 - 10
y = 2
The y coordinate of the vertex is k = 2
The vertex is (h,k) = (2,2)
Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | > a always have solutions of the form
x < - a or x > a, thus
2x + 1 < - 5 OR 2x + 1 > 5 ( subtract 1 from both sides of both inequalities
2x < - 6 OR 2x > 4 ( divide both sides of both inequalities by 2 )
x < - 3 OR x > 2
There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "
According to Pythagoras theorem,
note :
- p = perpendicular / opposite side
- b = base / adjacent side
- h = hypotenuse
let's solve for " y² " first ( square of other missing side )
now let's solve for " x " , by using pythagorous theorem
Approximate :
