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VladimirAG [237]
2 years ago
9

1.Solve : 3(5 + 7) - 4(8 + 4) = * 2.solve:-7 x -10 ill give you an free robux account if you get them correct

Mathematics
1 answer:
Kaylis [27]2 years ago
7 0

Answer:

1) -12, 2) 70

Step-by-step explanation:

Hope this helps :)

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Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
2 years ago
A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o
krok68 [10]

Answer:

you need to convert pounds to kilograms. 196 pounds is 88.904 kilograms. The directions tell you that 20 milligrams of the drug is to be administered for each kilogram of a person's weight. Now you need to multiply 88.904 by 20. That should give you 1778.08 milligrams of lincomycin. You would then mix 250 cc's of saline solution to the 1778.08 milligrams of lincomycin; but I think its just asking you how much lincomycin to administer.

at what rate per minute should the 250 cc solution be adminstered

4 0
3 years ago
Use Inverse Operations to solve.Check Your Answer<br><br> 17 + k = 54
lesya [120]
When you do the inverse operation which in this case would be subtraction you do  54-17 and then you do 17 minus 17 which leaves you with the variable 54-17=34 so k=34

8 0
2 years ago
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Angie and Kim are sharing a large sub sandwich. Angie ate
VikaD [51]

They ate 2/3 together. And, they have 1/3 left!

7 0
3 years ago
Which equation is equal up to one-hundredth of 36? Is it 0.3*0.12 or 0.36÷0.12 or 0.3*1.2
Mumz [18]
Its 360 beacuse u multiply all of those numbers


3 0
3 years ago
Read 2 more answers
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