Answer:
Well, I'm not sure what you mean but Ptolemy's Theorem gives a relationship between the side lengths and the diagonals of a cyclic quadrilateral; it is the equality case of Ptolemy's Inequality. Ptolemy's Theorem frequently shows up as an intermediate step in problems involving inscribed figures.
New secured 4.5 is the best option
It the talk empty side it will be 8 and the line will be 4 tell me if I am wrong
You can only add exponents if you are multiplying two of the same variable together. For example,

You take them away if you are dividing.
<span>

In a polynomial equation, you can add together two of the same variable if they have the same exponent
</span>

Or you can take them away in a similar fashion,
<span>

But you cannot add two (or more) different exponents,
</span>

(it does not get any simpler)
I hope this has answered your question, if not, leave a comment and I'll update the answer.
7(4(1/2))+3(5(1/3))+2(-3(1/2))=
7(4/2)+3(5/3)+2(-3/2)=
7(2)+15/3+-6/2=
14+5-3=
19-3=
16