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timama [110]
3 years ago
5

If 1 mol of a pure triglyceride is hydrolyzed to give 2 mol of RCOOH, 1 mol of R'COOH, and 1 mol of glycerol, which of the follo

wing compounds might be the triglyceride?
CHOC(O)R
A. CHOC(O)R
CHOC(O)R
CH,OC(O)R
B. CHOC(O)R
CH2OC(O)R
CHOC(O)R
C. CHOC(O)R
CHOC(O)R
CHOC(O)R
D. CHOC(O)R
CHOC(O)R

Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

The correct option is C.

Note the full question and structure of the moleculesis found in the attachment below.

Explanation:

Triglycerides or triacylglycerols are non-polar, hydrophobic lipid molecules composed of three fatty acids linked by ester bonds to a molecule of glycerol.

The fatty acids linked to the glycerol molecule are denoted by R and may be of the same kind or different. when the R group is the same, the R is attached in all the three positions for ester bonding in the glycerol molecule but when they are different are denoted by R, R' and R'' respectively.

During the hydrolysis of triglycerides, the three fatty acids molecules are obtained as well as a glycerol molecule.

From the question, when 1 mole of the triglyceride is hydrolysed, 2 moles of RCOOH, 1 mole of R'COOH and 1 mole of glycerol is obtained. The triglyceride must then be composed of two fatty acids which are the same denoted by R, and a different fatty acid molecule denoted by R'.

The correct option therefore, is C

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Answer:

228 mL

Explanation:

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3 0
3 years ago
Convert 5.00 moles of carbon to grams. Be sure to report your answer with the correct significant figures.
sergij07 [2.7K]

1 moles Carbon to grams = 12.0107 grams

2 moles Carbon to grams = 24.0214 grams

3 moles Carbon to grams = 36.0321 grams

4 moles Carbon to grams = 48.0428 grams

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6 moles Carbon to grams = 72.0642 grams

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8 moles Carbon to grams = 96.0856 grams

9 moles Carbon to grams = 108.0963 grams

10 moles Carbon to grams = 120.107 grams

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3 years ago
If a scientist has a 105 mL solution of 0.08 M HCl, then to a good approximation, what will be the pH of the solution? Enter you
djyliett [7]

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Explanation:

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3 years ago
A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent
rusak2 [61]

Answer:

\boxed{4.7\times 10^{-9}}

Explanation:

Data:

MM = 848.952 g/mol  

   c = 4.0 x 10⁻⁶ g/L

  V = 1 L

Calculations:

(a) Mass of growth hormone

\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}

(b) Moles of growth hormone

\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}

8 0
4 years ago
16.25 g of water at 54 C relaeases 402.7 J. What will be its final temp?
leonid [27]
Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?

Solving:

Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
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\Delta\:T =  \frac{-402.7}{67.99}
\boxed{\Delta\:T \approx -5.92\:^0C}

If: ΔT (T final - T initial) = ?
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T_{final} = 54^0 - 5.92^0
\boxed{\boxed{T_{final} = 48.08\:^0C}}\end{array}}\qquad\quad\checkmark

8 0
4 years ago
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