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blondinia [14]
3 years ago
7

How does carbon enter soil?

Chemistry
2 answers:
Umnica [9.8K]3 years ago
6 0
Animals and plants get rid of carbon<span> dioxide gas through a process called respiration. </span>Carbon<span> moves from fossil fuels to the atmosphere when fuels are burned. When humans burn fossil fuels to power factories, power plants, cars and trucks, most of the </span>carbon<span> quickly </span>enters<span> the atmosphere as </span>carbon<span> dioxide gas. I hope this works!

</span>
svet-max [94.6K]3 years ago
5 0
When something carbon based is in the soil. For example when you bury a cat or a body, it slowly decomposes, that carbon that was in the body gets absorbed by the soil. It goes back to the earth. That soil with "new" carbon is soil rich in nutrients etc. hope this helps
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If you have 3.0 moles of argon gas at STP, how much volume will the argon take up?
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If you have 3.0 moles of argon gas at STP u would take up 2.5 volume
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If 35.8 grams of LiCl are dissolved in 184 grams of water, what is the concentration of the solution in percent by mass?
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Jada Peterson
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Answer: A

Explanation:

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Calculate the number of atoms of argon in 75.0 L of argon at STP.<br> ?????
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A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
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Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

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Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
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