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san4es73 [151]
3 years ago
6

If you have 3.0 liters of an unknown gas, at standard temperature and pressure conditions, then you can calculate what about tha

t gas?
mass

density

moles of representative particles

mass and moles of representative particles
Chemistry
2 answers:
Ivenika [448]3 years ago
5 0
Density I'm pretty sure
EastWind [94]3 years ago
4 0

Hello!

<u><em>Answer: second option b density.</em></u>

____________________________________________________________

Explanation:

↓↓↓↓↓↓↓↓↓

Density is the amount of mass in a given volume. Density is the ratio of mass to volume. It's a derived unit of measure. It's equal to mass divided by the volume. It's measured in units such as grams per cubic centimeter and grams per milliliter.

Density formula:

↓↓↓↓↓↓↓↓

D=\frac{M}{V}

________________________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

_______________________________________________________________

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A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83
guapka [62]

Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

6 0
3 years ago
Cesium has a radius of 272 pm and crystallizes in a body-centered cubic structure. What is the edge length of the unit cell
olchik [2.2K]

Answer: Edge length of the unit cell = 628pm

Explanation: For a body centred cubic structured system, the relationship between the edge length of the unit cell and radius of the atoms in the structure is

Edge length of Unit cell (a) = (4R)/(√3)

R = 272pm = (272 × (10^-12))m = (2.72 × (10^-10))m

a = (4 × (2.72 × (10^-10)))/(√3)

a = (6.28157 × (10^-10))m = 628pm

4 0
2 years ago
2K2SO4 &lt;--- how many atoms are there in this formula?
jekas [21]
There are 14 atoms, the 2 at the front times' everything by 2, so there 4Ks, 2Ss and 8Os, altogether 14
3 0
3 years ago
Ionic salts are used for melting ice on roads for two reasons: they are effective at lowering the freezing point when they disso
Anuta_ua [19.1K]

Answer:

CaCl2=1

KCl=3

Explanation:

CaCl2 has a very high heat of solution hence it is best at melting ice. It is better than all the other salts mentioned. Its dissolution in water produces a lot of heat which melts the ice.

3 0
3 years ago
Read the given chemical reaction.
k0ka [10]
It is d
D is for you
6 0
3 years ago
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