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san4es73 [151]
3 years ago
6

If you have 3.0 liters of an unknown gas, at standard temperature and pressure conditions, then you can calculate what about tha

t gas?
mass

density

moles of representative particles

mass and moles of representative particles
Chemistry
2 answers:
Ivenika [448]3 years ago
5 0
Density I'm pretty sure
EastWind [94]3 years ago
4 0

Hello!

<u><em>Answer: second option b density.</em></u>

____________________________________________________________

Explanation:

↓↓↓↓↓↓↓↓↓

Density is the amount of mass in a given volume. Density is the ratio of mass to volume. It's a derived unit of measure. It's equal to mass divided by the volume. It's measured in units such as grams per cubic centimeter and grams per milliliter.

Density formula:

↓↓↓↓↓↓↓↓

D=\frac{M}{V}

________________________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

_______________________________________________________________

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Transition metals often form ions with a charge of _____-
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A quantity of 0.225 g of a metal M (molar mass = 27.0 g/mol) liberated 0.303 L of molecular hydrogen (measured at 17°C and 741 m
Lana71 [14]

Answer:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3

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0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

Pressure of the gas ,P= 741 mmHg= 0.9633 atm

Volume occupied by gas , V = 0.303 L

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol

Moles of hydrogen gas produced = 0.01225 mol

2M+2xHCl\rightarrow 2MCl_x+xH_2

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So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

\frac{8.3333}{0.01225 mol}=\frac{2}{x}

x = 2.9 ≈ 3

2M+6HCl\rightarrow 2MCl_3+3H_2

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Formulas for the oxide and sulfate of M will be:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3.

3 0
3 years ago
At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at
kvv77 [185]

Answer:

speed=5cm/minute

Explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is  10 minutes = 10\times 60=600 seconds

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

speed=\frac{distane}{time}

speed=\frac{0.5}{600}

speed = 8.3\times 10^{-4} m/sec=5cm/minute

3 0
3 years ago
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