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3 years ago

I need helpppppp asappppp

Mathematics

1 answer:

andrew-mc [135]3 years ago

3 0

Answer:

A. 72cm

Step-by-step explanation:

Figure a is a convex pentagon, a convex pentagon is a pentagon that does not have an internal angle greater than

${180}^{0}$

An easier thing to remember is that it does not have an angle pointing inwards like b, none of its angles/edges point toward the shape/inside

You might be interested in

2/x + 3/y = 13 ; 5/x - 4/y = -2

Tomtit [17]

Given that

(2/x)+(3/y) = 13--------(1)

(5/x)-(4/y) = -2 -------(2)

Put 1/x = a and 1/y = b then

2a + 3b = 13 ----------(3)

On multiplying with 5 then

10a +15 b = 65 -------(4)

and

5a -4b= -2 ----------(5)

On multiplying with 2 then

10 a - 8b = -4 -------(6)

On Subtracting (6) from (4) then

10a + 15b = 65

10a - 8b = -4

(-)

_____________

0 + 23 b = 69

______________

⇛ 23b = 69

⇛ b = 69/23

⇛ b =3

On Substituting the value of b in (5)

5a -4b= -2

⇛ 5a -4(3) = -2

⇛ 5a -12 = -2

⇛ 5a = -2+12

⇛ 5a = 10

⇛ a = 10/5

⇛ a = 2

Now we have

a = 2

⇛1/x = 2

⇛ x = 1/2

and

b = 3

⇛1/y = 3

⇛ y = 1/3

Answer :-The solution for the given problem is (1/2,1/3)

Check: If x = 1/2 and y = 1/3 then

LHS = (2/x)+(3/y)

= 2/(1/2)+3/(1/3)

= (2×2)+(3×3)

= 4+9

= 13

= RHS

LHS=RHS is true

and

LHS=(5/x)-(4/y)

⇛ 5/(1/2)- 4/(1/3)

⇛(5×2)-(4×3)

⇛ 10-12

⇛ -2

⇛RHS

LHS = RHS is true

5 0

2 years ago

Select the graph that would represent the best presentation of the solution set. \absP > 3

m_a_m_a [10]

Answer:

Step-by-step explanation:

there's no graph selection attached. Can you upload it and then I can help?

4 0

2 years ago

The tens digit is 9 more than the ones digit my number is?

yKpoI14uk [10]

90 or 100 something like that.

5 0

3 years ago

The frequency table below shows the antenna careers among the incoming class of first-year college students. Every student is ch

neonofarm [45]

To solve this you must use a proportion like so...

$\frac{part}{whole} = \frac{part}{whole}$

The total number of students that can be chosen are 4,663. This number will represent the whole of one fraction in the proportion. We want to know what percent probability out of these students are engineer, medical doctor/surgeon. This would be considered the part of this fraction. Sum the number of engineering students (615) with medical doctors/surgeons (723) to find this number

723 + 615 = 1,338 students that want to be an engineer or medical doctor/surgeon

Percent's are always taken out of the 100. This means that the other fraction in the proportion will have 100 as the whole and x (the unknown) as the part.

Here is your proportion:

$\frac{1,338}{4,663} =\frac{x}{100}$

Now you must cross multiply

1,338*100 = 4,663*x

133,800 = 4,663x

To isolate x divide 4,663 to both sides

133,800/4,663 = 4,663x/4,663

28.7 = x

This means that there is a 28.7% of a student with the intent of becoming an engineer or a medical doctor/surgeon to be chosen at random

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0

2 years ago

Read 2 more answers

2.16 (the 6 is repeating) as a fraction (no improper fractions)

serg [7]

Answer:

2 4/25

Step-by-step explanation:

First, I made the decimal into 2 16/100. Then, keep simplifying the 16/100 until it is fully simplified.

6 0

3 years ago