6/15 + 10/15 = 16/15 = 1 1/15
6/15 - 10/15 = -4/15
The first perfect square that divides into 337 is
A second perfect square that divides into 337 is
The answer is x1= 0, x2= 6
If I'm understanding you correctly, you are asking to change x^(7/5) to x^3.
Raise x^(7/5) to the (15/7) power which yields x^3.