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erastovalidia [21]
3 years ago
7

Blank as 8 hundreds is 8 thousands?

Mathematics
2 answers:
e-lub [12.9K]3 years ago
6 0

Answer:

Ten times as 8 hundreds is 8 thousands.

Step-by-step explanation:

Ten times as 8 hundreds is 8 thousands.

This can be written mathematically as:

10 times as 800, is 8000.

or, we can multiply these to get the answer.

10\times800=8000

So, the answer is : Ten times as 8 hundreds is 8 thousands.

AlladinOne [14]3 years ago
3 0

Ten times as 8 hundreds is 8 thousands

The value of 8,000 is ten times the value of 800

<h2>Further Explanation  </h2><h3>Place value and total value  </h3>
  • Place value refers to the value represented by a digit in a number based of its position in the number. Place values can be ones, tens, hundreds, thousands, etc  
<h3>For example;</h3>

In the number; 24,621 the place value of the digits in the number are;

Ones -1

Tens - 2

Hundreds - 6

Thousands - 4

Ten Thousands – 2

<h3>Total value  </h3>
  • Total value is given as the product of the digit and its place value.
  • For example; in the number, 24,621 
  • Total value of digits 2,4,6,2 and 8 in the number 24,621 will be;

2 x 10,000 = 20,000

4 x 1000    = 4,000

6 x 100      = 600

2 x 10        = 20  

1 x 1          = 1

The sum of the total values of digits in a number will be equivalent to the value of that number.

Therefore; we would say that;

Ten times as 8 hundreds is 8 thousands, that is, the value of 8,000 is ten times the value of 800

Keywords: Place value, total value

<h3>Learn more about;</h3>
  • Types of number form: brainly.com/question/537230
  • Example of place value: brainly.com/question/537230
  • Example of total value: brainly.com/question/537230

Level: Middle school

Subject: Mathematics  

Topic: Place value and total value

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Step-by-step explanation:

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3 years ago
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If a = {6 6 4 7 -4 4 -6 9 -3} and B= {1 5 -8 9 -5 -8 9 -5 2}, find 3a +9B Matrix operations
V125BC [204]

Answer:

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Step-by-step explanation

  • A=\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix}\: and \: B=\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=3\begin{bmatrix} 6 & 6 & 4\\\\7 & -4 & 4\\\\ -6 & 9 & -3\end{bmatrix},\:  \: 9B =9\begin{bmatrix}1 & 5 & -8\\\\ 9 & -5 & -8\\\\ 9 & -5 & 2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 3*6 & 3*6 & 3*4\\\\3*7 & 3(-4) & 3*4\\\\ 3(-6) & 3*9 & 3(-3)\end{bmatrix},\:\: 9B =\begin{bmatrix}9*1 &9* 5 &9( -8)\\\\ 9*9 & 9(-5) & 9(-8)\\\\ 9*9 & 9(-5) & 9*2\end{bmatrix}

  • \rightarrow 3A=\begin{bmatrix} 18 & 18 & 12 \\\\ 21 & -12 & 12\\\\ -18 & 27 & -9\end{bmatrix},\:\: 9B =\begin{bmatrix} 9 & 45 & -72 \\\\ 81 & -45 & -72\\\\ 81 & -45 & 18\end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix}18+9 & 18+45 & 12+(-72) \\\\ 21+81 & -12 +(-45) & 12+(-72)\\\\ -18+81 & 27+(-45) & -9+18 \end{bmatrix}

  • \rightarrow 3A+9B=\begin{bmatrix} 18+9 & 18+45 & 12-72 \\\\ 21+81 & -12 -45 & 12-72\\\\ -18+81 & 27-45 & -9+18 \end{bmatrix}

  • \rightarrow \purple{\bold{3A+9B=\begin{bmatrix} 27 & 63 & -60 \\\\ 102 & -57 & -60\\\\ 63 & -18 & 9 \end{bmatrix}}}
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2 years ago
I need help on number 4. Please help me!
Andreas93 [3]
S= R- 1/3R

The first problem s=18 r-= 6
This is how it works

Use S-= R-1/3R
12= 18-1/3(18)
12= 18-6
12=12

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3 years ago
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3)we calculate the second derived
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4) Now we calculate the value of "y".
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Therefore; Exist a minimum at (-4.5 , -24.5)
7 0
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