Answer: u have perpendicular lines
Step-by-step explanation: Hope this helps :)
The area is 76 ft squared, and the perimeter is 43.1 ft. CORRECT ME IF IM WRONG BECAUSE I WAS SO BAD AT AREA/PERIMETER
Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
0 + 0 + 5 = 5
0 + 2 + 6 = 8
6 + 7 + 4 = 17
Put the 7 in the appropriate column and carry the 1.
<span>8 + 9 + 7 + </span><span>1(carried)</span><span> = 25</span>
Put the 5 in the appropriate column and carry the 2.
<span>9 + 5 + </span><span>2(carried)</span><span> = 16</span>
Put the 6 in the appropriate column and carry the 1.
<span>2 + </span><span>1(carried)</span><span> = 3</span>
<span>So: 1493 × 245 = 365785</span>