The Unit Circle

Mathematics

1 answer:

Makovka662 [10]3 years ago

8 0

Answer:

B. (0.87, 0.48)

Step-by-step explanation:

I calculated it logically

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On a coordinate plane, a point is at (negative 4, negative 4) and (negative 4, negative 10).

Valentin [98]

Answer:

Option C.

Step-by-step explanation:

Hey there!

The points are; (-4,-4) and (-4,-10).

Use distance formula.

$d = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

~ Put all values.

$d = \sqrt{ {( - 4 + 4)}^{2} + ( { - 10 + 4)}^{2} }$

~ Simplify it.

$d = \sqrt{ {0}^{2} + ( { - 6)}^{2} }$

$d = \sqrt{36}$

Therefore, distance between the points is 6 units.

Hope it helps...

6 0

3 years ago

If two straight lines intersect and one angle is 30 degrees what are the other three angles

mel-nik [20]

Easey peasy
oposite angle is equal
other angles are supplementary (supplementary means add to 180, and a straight line=180 so if you look at 2 lines intersecting and think for a little bit, you wiill see why)

oposite angle=30
other angle is adds to 180
30+other=180
subtract 30
other=150
other is oposite other other
other=other other
150=other other

angles are
150,30,150

3 0

3 years ago

Read 2 more answers

Given: ABCD is a rhombus. Prove: △AEB is a right triangle.

lukranit [14]

Answer:

Step-by-step explanation:

∵ ABCD is a rhombus

∴ AC is ⊥ on BD

∴ ΔAEB is right angled triangle

4 0

3 years ago