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dezoksy [38]
3 years ago
11

6i) {}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

36i^{2}+48i+16

Step-by-step explanation:

(4+6i)^{2} is essentially (4+6i)(4+6i) (you are squaring (4+6i), so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

(4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i) >> (4+6i)(4+6i)

((4*4)+(4*6i)+(6i*4)(6i*6i))

After doing so, you would end up with 16+24i+24i+36i^{2}, and after combining like terms, 16+48i+36i^{2}.

To write the expression in standard form, though, just order the terms from highest to lowest power!

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3 years ago
Please answer the question in the picture and show your work! I got tan= square root of 2 but I’m not sure if that’s right and i
melomori [17]

Answer:

tan(θ) is undefined.

Step-by-step explanation:

Recall that tan(θ) = sin(θ) / cos(θ). We are given that sin(θ) = -1. Hence:

\displaystyle \tan\theta=\frac{\sin\theta}{\cos\theta}=-\frac{1}{\cos\theta}

Since 1 / cos(θ) = sec(θ):

\tan\theta=-\sec\theta

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From the Pythagorean Identity:

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Substitute:

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So:

1\neq0

Since we acquire an untrue statement, no solutions exist.

If needed, refer to the unit circle. Recall that sin(θ) only equals -1 when θ = 3π/2 (on the interval [0, 2π)). At 3π/2, cos(θ) = 0. Since tan(θ) = sin(θ) / cos(θ), tan(θ) is undefined whenever sin(θ) = -1 (or 1).

6 0
3 years ago
Tell whether (-3, 3) is a solution of the system.​
pickupchik [31]
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3 0
3 years ago
Read 2 more answers
The diagonals of a kite _____.
Vikentia [17]

Answer:

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We should know the properties of kite.

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Thank you.

5 0
3 years ago
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Tanzania [10]

Answer:

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Step-by-step explanation:

\frac{6}{5}  =  \frac{n}{15}

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\frac{90}{5}  =  \frac{5n}{5}

Simplify : Cross cancel common factor: 5

18 = n \\ n = 18

7 0
3 years ago
Read 2 more answers
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