Question

6i) {}^{2} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$36i^{2}+48i+16$

Step-by-step explanation:

$(4+6i)^{2}$ is essentially $(4+6i)(4+6i)$ (you are squaring $(4+6i)$, so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

$(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$

($(4*4)+(4*6i)+(6i*4)(6i*6i)$)

After doing so, you would end up with $16+24i+24i+36i^{2}$, and after combining like terms, $16+48i+36i^{2}$.

To write the expression in standard form, though, just order the terms from highest to lowest power!