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3 years ago

Each polygon pair is similar. Find the missing side length

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

I'll do problem 1 to get you started.

The vertical sides are 3 and x for the left and right figures.

The horizontal sides are 15 and 60 for the left and right figures.

The corresponding sides form fractions which are equal (due to the nature of the similar polygons)

3/x = 15/60

3*60 = x*15 ... cross multiply

180 = 15x

15x = 180

x = 180/15 .... divide both sides by 15

x = 12

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Another way you can see this is note how the jump from 15 to 60 is "times 4", so the jump from 3 to x must also be "times 4" to keep the same proportion

3 ---> x = 3*4 = 12

Or you could set up the proportion

60/15 = x/3

4 = x/3

x/3 = 4

x = 3*4

x = 12

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<h3>Final Answer: 12</h3>

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4 years ago

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And replacing we got:

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Step-by-step explanation:

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X 1 2 3 4

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For this case we can calculate the epected value with this formula:

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And replacing we got:

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3 years ago

Please help me with this math homework thanks :)

Ivenika [448]

Place a point at (0,-5) because that is the y-intercept (the -5 on the vertical line)

Since the slope is negative two which can be re-written as -2/1 (rise/run) you go down two and to the right once or up two and to the left once, it doesn't matter which. Another point can be placed at (1,-7) or (-3,-1), it still doesn't matter which.

Then you can draw a line connecting the two points.

I hope this helps :)

Let me know if you need further explanation