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FinnZ [79.3K]
3 years ago
6

What problem cannot be solved using the law of sines?

Mathematics
1 answer:
Radda [10]3 years ago
3 0
<span>When to use the law of sines formula. You should use the law of sines when you know 2 sides and an angle and you want to find the measure of an angle opposite a known side. Or when you know 2 angles and 1 side and want to get the side opposite a known angle.</span>
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CLICK HERE IF YOU HAVE BIG FEET <br><br> Using the function g( x) = -2 x – 11, calculate g(-3).
Leokris [45]

════════ ∘◦❁◦∘ ════════

<h3>Answer = -5</h3>

════════════════════

<h3>Known</h3>

g(x) = -2x - 11

════════════════════

<h3>Question</h3>

g(-3) = ..?

════════════════════

<h3>Way to do</h3>

#since x inside (x) change into (-3) then it means that you only need to change x into -3

g(-3) = -2(-3) - 11

g(-3) = 6 - 11

g(-3) = -5

════════════════════

6 0
3 years ago
For the graph shown, select the statement that best represents the given system of equations. Number graph ranging from negative
Bumek [7]
This system of equations is consistent and independent, because there is only one solution. the answer is C
7 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!
bekas [8.4K]

Answer:

  1. reflection across BC
  2. the image of a vertex will coincide with its corresponding vertex
  3. SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

  • side AB and side GB
  • side AC and side GC
  • angle ABC and angle GBC
  • angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

  • side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

  • SSS -- three pairs of corresponding sides
  • SAS -- two corresponding sides and the angle between
  • ASA -- two corresponding angles and the side between
  • AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0
1 year ago
Read 2 more answers
Tan x + sqrt(3) = - 2 tan x
Svet_ta [14]

9514 1404 393

Answer:

  nπ -π/6 . . . for any integer n

Step-by-step explanation:

  tan(x) +√3 = -2tan(x) . . . . . given

  3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

  tan(x) = -√3/3 . . . . . . . . . . divide by 3

  x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

  x = n·π -π/6 . . . . for any integer n

8 0
2 years ago
Plz help will mark brainliest :)
shepuryov [24]

Answer:

an odd    an even

Step-by-step explanation:

plz mark as brainliest. my first answer

3 0
3 years ago
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