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3 years ago

Which calculation will ALWAYS give a result greater than 1?

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

8 0

Answer:

The correct option is C: 1 2/5 - a fraction less than 2/5 .

Step-by-step explanation:

Consider the provided information.

We want the result is always greater than 1.

A: 8/9 x a number less than 1.

8/9 = 0.88... if we multiply it with a number less than 1, the result will always less than 1.

For example:

0.88... × 0.999.. = 0.88...

Thus, the option is incorrect.

B: 7 x a number less than 1

7 multiply a number less than 1 will not ALWAYS give a result greater than 1

For example:

7 × 0.01 = 0.07

Thus, the option is incorrect.

C: 1 2/5 - a fraction less than 2/5

1 2/5 = 7/5 or 1.4

2/5 = 0.4

If we subtract 1.4 from 0.4 the result will 1. But it is given that we can subtract a fraction less than 2/5.

That means the result will always greater than 1.

For example:

1.4 - 0.399999 = 1.000001

Which is greater than 1.

Thus, the option is correct.

D: 3/7 + a number less than 1/2

3/7 = 0.4286 (Approximately)

1/2 = 0.5

If we will add them the result will always less than 1.

So the sum of 3/7 and a number less than 1/2 will always less than 1.

Thus, the option is incorrect.

Hence, the correct option is C: 1 2/5 - a fraction less than 2/5 .

Mazyrski [523]3 years ago

3 0

C is the answer, because the statmen placed on this one is true 1&3/4 is actually greater then 3/4 when if you just left that 1 & 3/4 with just a one it would still be greater.

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Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

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Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "-1 to the fourth."