Answer:
- <u>It is a combination</u>
<u></u>
Explanation:
This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.
The formula for combinations is:

For five diffferent dogs to be put in pairs, the number of different pairs is:

Answer:
No solution
Step-by-step explanation:

Lets consider the equation 2.
Here we multiply the LHS and RHS with (-1).

Hence,

When we add the equations we get,

As 0 doesn't equal to -1, answer is d) No solution
To find the answer to a problem like this, we need to look for patterns in the number!
It looks likes x = 2y
Or in other words, (y is being multiplied by 2 to find x!)
**Now that we've discovered this pattern, we can confidently say that ...
<u>the number</u><u> 6</u><u> belongs in</u><u> #1 </u>
Answer:
C≈125.66
Step-by-step explanation: