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BARSIC [14]
3 years ago
14

Prove that ΔABC and ΔEDC are similar.

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

∠DCE is congruent to ∠CBA by the Vertical Angles Theorem and 15 over 5 equals 12 over 4 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate.

Step-by-step explanation:

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steposvetlana [31]

Answer:

\huge\boxed{\sf Discriminant = -4}

Step-by-step explanation:

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\rule[225]{225}{2}

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