Is the quadrilateral a parallelogram? No Yes Not enough info
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Okay, so first you are going to decide whether to solve for x or solve for y. I am going to solve for x. In order to do so, you must get x by itself.
![2x=y-6[ [tex]3x-4y=-4](https://tex.z-dn.net/?f=2x%3Dy-6%5B%20%5Btex%5D3x-4y%3D-4)
The next step is to set both equations equal to each other in order to find y.
\frac{y-
6}{2} [/tex]
So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.
So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.
The next step is to set both equations equal to each other in order to find y.
\frac{y-
So now you know that y=-2. The next part is substitution. All you have to do is pick on of the equations and plug in the y value to get the x value.
So your answer to the question is (-4,-2). I hope I've helped you understand how to solve these types of problems. If you have any questions, don't hesitate to ask.