We turn -5,12 into polar coordinates. It's a Pythagorean Triple so
r = 13 Ф=arctan(-12/5) + 180° ( in the second quadrant )
so -5 = 13 cos Ф, 12 = 13 sin Ф
12 sin x - 5 cos x = 6.5
13 sinФ sin x + 13 cos Ф cos x = 6.5
13 cos(x - Ф) = 6.5
cos(x - Ф) = 1/2
cos(x - Ф) = cos 60°
x - Ф = ± 60° + 360° k integer k
x = Ф ± 60° + 360° k
x = 180° + arctan(-12/5) ± 60° + 360° k
That's the exact answer;
x ≈ 180° - 67.38° ± 60° + 360° k
x ≈ 122.62° ± 60° + 360° k
x ≈ { 62.62°, 182.62°} + 360° k, integer k
I'm NOT 100% confident in my answers.
Graph 1:
Range: Option B
Graph 2:
Range: Option A
The range has to start at zero since that's the lowest point we can go, only one with zero is first option.
RATE AS BRAINLIEST
Answer:
132°
Step-by-step explanation:
∠AOB = ∠EOD = 3x ( vertical angles )
∠AOB + ∠BOC = 90, that is
3x + 0.5x + 34 = 90
3.5x + 34 = 90 ( subtract 34 from both sides )
3.5x = 56 ( divide both sides by 3.5 )
x = 16
∠AOE + ∠EOD = 180 ( straight angle )
∠AOE + 3x = 180
∠AOE + (3 × 16) = 180
∠AOE + 48 = 180 ( subtract 48 from both sides )
∠AOE = 132°
Thank you sooo much Maddi441
