Write an equation of the line that passes through (-2,3) and is parallel to the line y=2x-4

Mathematics

1 answer:

anzhelika [568]4 years ago

3 0

Answer:

Equation: y = 2x + 7

Step-by-step explanation:

If the line is parallel to the line resembling the equation y = 2x - 4, it would mean that the line would have a similar slope, leading to part of the equation:

y = 2x

Now substitute the x-coordinate -2 and y-coordinate 3 into the equation * (derived from (-2, 3) ):

3 = 2(-2)

Now simplify either side:

3 = -4

For 3 to equal -4, you would have to add 7:

3 = -4 + 7 = 3

This means the final equation is:

y = 2x + 7

(Sorry if this isn't the way you expected to solve the question)

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$if \ (a^x)^y = a^{xy}\\\\ (2^2)^6 = 4,096\\\\(4)^6 = 4,096\\\\Thus, \ the \ first \ whole \ number \ is \ 4\\\\(2^3)^4 = 4,096\\\\(8)^4 = 4,096\\\\Thus, \ the \ second \ whole \ number \ is \ 8\\\\(2^4)^3 = 4,096\\\\(16)^3 = 4,096\\\\Thus, \ the \ third \ whole \ number \ is \ 16\\\\(2^6)^2 = 4,096\\\\(64)^2 = 4,096\\\\Thus, \ the \ fourth \ whole \ number \ is \ 64$