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Eduardwww [97]
3 years ago
7

Write an equation of the line that passes through (-2,3) and is parallel to the line y=2x-4

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

Equation: y = 2x + 7

Step-by-step explanation:

If the line is parallel to the line resembling the equation y = 2x - 4, it would mean that the line would have a similar slope, leading to part of the equation:

y = 2x

Now substitute the x-coordinate -2 and y-coordinate 3 into the equation * (derived from (-2, 3) ):

3 = 2(-2)

Now simplify either side:

3 = -4

For 3 to equal -4, you would have to add 7:

3 = -4 + 7 = 3

This means the final equation is:

y = 2x + 7

(Sorry if this isn't the way you expected to solve the question)

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What is the difference?
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Answer:

<h2>D. \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression \frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }, the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\

Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

The final expression gives the difference

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Step-by-step explanation:

-2x=30-120

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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