Answer:
y = 0
x = -4
( x, y ) = ( -4 , 0 )
Step-by-step explanation:
y = 5x + 20
y = -2x - 8
Substitute
5x + 20 = -2x - 8
Add 8 on both sides
5x + 20 + 8 = -2x - 8 + 8
5x + 28 = -2x
Subtract 5x on both sides
5x - 5x + 28 = -2x - 5x
28 = -7x
Divide by -7 on both sides
28/-7 = -7x/-7
-4 = x
Now that you have x, you can substitute it in one of the equations that was given to find the value of y.
y = 5x + 20
y = 5(-4) + 20
y = -20 + 20
y = 0
Or....
y = -2x - 8
y = -2(-4) - 8
y = 8 - 8
y = 0
They will both be 0 no matter what
Point form = ( -4, 0 )
Hope this helped
Answer:
22 + 27 = <u><em>49</em></u>
<u><em></em></u>
:) :)
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
Answer:
Is there a picture?
Step-by-step explanation:
Answer: Substitution
Step-by-step explanation:
Because you know A is equal to B, you can substitute A for B in any mathematical equation. Essentially, you are switching mA $ mB.
