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gayaneshka [121]
3 years ago
11

A lighthouse casts a 128-ft shadow. A nearby lamppost that measures 5

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer: 80 feet

Step-by-step explanation:

We can write these as fractions and do cross multiplication with the numerator being the height of the object while the denominator being the length of the shadow:

5 * 128 = 8x

640 = 8x

80 = x

Thus, the height of the lighthouse is 80 feet tall.

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3x^3(4x^4)=?<br> i need this plz
sladkih [1.3K]

Answer:

12 x^{7}

Step-by-step explanation:

3 0
3 years ago
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Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i
mash [69]

Complete Question

A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?

Answer:

The  margin of error is  E = 0.7

The  sample mean is  \=  x  =  4.2

Step-by-step explanation:

from the question we are told that

   The  upper limit is  k  =  4.9

    The  lower limit is  r = 3.5

Generally the margin of error is mathematically represented as

      E =  \frac{k - r}{ 2}

      E = \frac{ 4.9  -  3.5 }{2}

     E = 0.7

Generally the sample mean is mathematically evaluated as

        \=  x = k  -  E

=>    \= x  =  4.9 - 0.7

=>    \=  x  =  4.2

4 0
3 years ago
I NEED HELP PLEASE!!
prohojiy [21]
60% decimal = .6 fraction= 6/10
3/4 percent =75% (think of $$) decimal =.75
0.23 percent =23% fraction= 23/100
1/8 percent= 12.5 decimal = 0.125
18% decimal= .18 fraction= 18/100 (simplified to 9/50)
2/3 percent=0.6% repeating (so put a line over 6) decimal= 0.6 repeating aswell so do the same as last
Your welcome :)
5 0
3 years ago
What three dimensional solid has 6 rectangular faces, 2 equal bases that are not rectangles, and 18 edges
lapo4ka [179]

A hexagonal prism should work! The two bases are hexagons, and there are 6 lateral faces that are rectangles. When you count the edges, there are 18

5 0
3 years ago
Read 2 more answers
A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs
Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

C = \frac{N!}{(N-K)!*K!}

For the juniors we have N = 13 and K = 6

Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716

For the seniors we have N = 16 and K = 8

Cs = \frac{16!}{8!8!}  = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0
3 years ago
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