This process involves the dilution of the 12 molar HCl. To reduce the concentration, we need to set up an equality so that we know how much of the 12M we need to make the 3.5M.
12 moles HCl 3.5 moles HCl
——————— = ———————
1 Liter of Soln ‘x’ Liters of Soln
Notice that the 12 moles over the 1 liter is equal to 12 molar; in doing this, we’re maintaining the concentration of the initial HCl. By setting it equal to the 3.5 over ‘x’, we’re still maintaining the concentration.
After solving, we find that ‘x’ equals 0.292. This value means that in 0.292 liters of our 12 M HCl solution, there are 3.5 moles of HCl. But, we’re not done yet.
0.292 liters of 12 M HCl can make 1 liter of 3.5 M HCl, but the question asks for 1.5 liters. To get this, multiply 0.292 liters by 1.5, and the new result, 0.4375, represents the amount of 12 M HCl required to prepare a 1500 mL 3.5 M HCl solution.
Matter and substance are definitely related. All substances
are matter but all matters are not substance. A matter can consist of numerous
substances. Matter is generally a loose term used in respect to a substance.
Any physical object can be casually called a matter. Matter and substance are
sometimes used for the same context, but it is completely wrong. Numerous
examples have already proved that a matter may or may not be a substance
depending on its physical nature, but a substance is always a matter.
Answer:
59.2 grams
Explanation:
We are given that 70.4% of the weight of the total 200 g of the concentration is made up of nitric acid, the remaining information is not required to solve the problem. Since water and nitric acid are the only components of the solution, the total weight of water is given by:
There are 59.2 grams of water in this solution.
Answer: 38.111111
Explanation: (100.6°F − 32) × 5/9 = 38.111°C
