Question

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g sucrose in 0.750 L solution?

Answer 1

To get the molarity, you divide the mass in moles over the amount in liters. To convert the grams to moles, divide the amount of grams by the molar mass. In this case, I believe sucrose has a molar mass of 342.297. Once you divide 171/342.297 you should get .4996. Now divide that by the .750 to get a final answer of .6660. Check to make sure you don't have to follow the significant figure rules.

Answer 2

Answer:

The answer is 0.67 M

Explanation:

Sucrose solution molarity= $\frac{mol sucrose}{1 L solution}$

You have to divide the mass of sucrose (171 g) by the molecular weight of sucrose (342 g/mol) and then divide the result by the volume in liters (0.750 L) as follows:

Molarity= $\frac{1 mol sucrose}{342 g}$ x $\frac{171 g sucrose }{0.750 L }$

Molarity= 0.666 mol sucrose/L

Molarity= 0.67 M