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DENIUS [597]
3 years ago
10

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g suc

rose in 0.750 L solution?
Chemistry
2 answers:
Elodia [21]3 years ago
7 0
To get the molarity, you divide the mass in moles over the amount in liters. To convert the grams to moles, divide the amount of grams by the molar mass. In this case, I believe sucrose has a molar mass of 342.297. Once you divide 171/342.297 you should get .4996. Now divide that by the .750 to get a final answer of .6660. Check to make sure you don't have to follow the significant figure rules.
pentagon [3]3 years ago
5 0

Answer:

The answer is 0.67 M

Explanation:

Sucrose solution molarity= \frac{mol sucrose}{1 L solution}

You have to divide the mass of sucrose (171 g) by the molecular weight of sucrose (342 g/mol) and then divide the result by the volume in liters (0.750 L) as follows:

Molarity= \frac{1 mol sucrose}{342 g} x \frac{171 g sucrose }{0.750 L }

Molarity= 0.666 mol sucrose/L

Molarity= 0.67 M

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mariarad [96]

The balanced reaction is 3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s ).

<u>Explanation</u>:

A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.

The unbalanced chemical equation is as follows,

                             Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )

To balance this equation, you need to look at how many atoms of each element are present on each side of the chemical equation.

 Calcium has  1  atom on the reactant and  3  on the products side. To balance the reaction we need to multiply the calcium atom by  3  on the reactants side.

                            3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )    

Now  Nitrogen has a coefficient of  2  on both sides of the reaction. Hence the balanced chemical equation will thus be

                              3 Ca ( s ) + N 2 ( g )  →  Ca 3 N 2 ( s )

3 0
3 years ago
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vesna_86 [32]

Answer:

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Explanation:

5 0
3 years ago
If 35.4 liters of hydrogen gas are used, how many liters of nitrogen gas will be needed for the above reaction at STP?
CaHeK987 [17]

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5 0
2 years ago
If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?
lara31 [8.8K]

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

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2 years ago
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AlladinOne [14]

Answer:

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Explanation:

3 0
2 years ago
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