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Elan Coil [88]
3 years ago
14

There are 6 yellow, 4 orange, 2 green, and five blue plastic building blocks all the same

Mathematics
1 answer:
Andru [333]3 years ago
3 0

We want to get the probability of selecting an orange, putting it back, then  selecting a block that is not orange.

We will see that the probability is P = 0.1799

In the bag we have:

  • 6 yellow blocks
  • 4 orange blocks
  • 2 green blocks
  • 5 blue blocks.

For a total of 6 + 4 + 2 + 5 = 17 blocks.

First we want to find the probability of getting an orange block, as all the blocks have the same probability of being randomly drawn, the probability of randomly drawing an orange block is equal to the quotient between the number of orange blocks and the total number of blocks.

We get:

p = 4/17

Now we put the orange block back and we want to take a block that is not orange, the probability is computed in the same way:

q = (6 + 2 + 5)/17 = 13/17

The joint probability (this is, the probability of these two events happening together) is just the product of the individual probabilities.

We get:

P = p*q = (4/17)*(13/17) = 52/289 = 0.1799

If you want to learn more, you can read:

brainly.com/question/1349408

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3 years ago
The cost for Andrea to produce several units of a certain item is $336 plus $12 per unit. She sells this item for $28 per unit.
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3 years ago
Compute the lower Riemann sum for the given function f(x)=x2 over the interval x∈[−1,1] with respect to the partition P=[−1,− 1
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Answer:

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Step-by-step explanation:

First, we need to note that the function f(x) = x² is increasing on (0, +∞), and it is decreasing on (-∞,0)

The first interval generated by the partition is [-1, -1/2], since f is decreasing for negative values, we have that f takes its minimum values at the right extreme of the interval, hence -1/2.

The second interval is [-1/2, 1/2]. Here f takes its minimum value at 0, because f(0) = 0, and f is positive otherwise.

Since f is increasing for positive values of x, then, on the remaining 2 intervals, f takes its minimum value at their respective left extremes, in other words, 1/2 and 3/4 respectively.

We obtain the lower Riemman sum by multiplying this values evaluated in f by the lenght of their respective intervals and summing the results, thus

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= 1/4 * 1/2 + 0 * 1 + 1/4 * 1/4 + 9/16 * 1/4 = 1/8 + 0 + 1/16 + 9/64 = 21/64

As a result, the lower Riemann sum on the partition P is 21/64

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