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Elan Coil [88]
3 years ago
14

There are 6 yellow, 4 orange, 2 green, and five blue plastic building blocks all the same

Mathematics
1 answer:
Andru [333]3 years ago
3 0

We want to get the probability of selecting an orange, putting it back, then  selecting a block that is not orange.

We will see that the probability is P = 0.1799

In the bag we have:

  • 6 yellow blocks
  • 4 orange blocks
  • 2 green blocks
  • 5 blue blocks.

For a total of 6 + 4 + 2 + 5 = 17 blocks.

First we want to find the probability of getting an orange block, as all the blocks have the same probability of being randomly drawn, the probability of randomly drawing an orange block is equal to the quotient between the number of orange blocks and the total number of blocks.

We get:

p = 4/17

Now we put the orange block back and we want to take a block that is not orange, the probability is computed in the same way:

q = (6 + 2 + 5)/17 = 13/17

The joint probability (this is, the probability of these two events happening together) is just the product of the individual probabilities.

We get:

P = p*q = (4/17)*(13/17) = 52/289 = 0.1799

If you want to learn more, you can read:

brainly.com/question/1349408

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Answer:.5%

Step-by-step explanation:

8 0
3 years ago
DJ Titus is making a playlist for a radio show; he is trying to decide what 10 songs to play and in what order they should be pl
Dominik [7]

Answer:

Different playlists possible = 18287141644800

Step-by-step explanation:

Given - DJ Titus is making a playlist for a radio show; he is trying to

            decide what 10 songs to play and in what order they should be

            played.

            Step 1 of 2 : If he has his choices narrowed down to 7 blues,

                                 7 disco, 5 pop, and 7 reggae songs.

To find - He wants to play no more than 4 reggae songs.

              How many different playlists are possible ?

Proof -

Given that he wants to play no more that 4 reggae songs.

So the possibility of choice of reggae song is 0, 1, 2, 3, 4

Now,

Case I -

If 0 reggae song is selected

⇒All 10 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₁₀ ₓ ⁷C₀ = 92,378

Case II -

If 1 reggae song is selected

⇒All 9 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₉ ₓ ⁷C₁ = 646,646

Case III -

If 2 reggae song is selected

⇒All 8 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₈ ₓ ⁷C₂ = 1,587,222

Case IV -

If 3 reggae song is selected

⇒All 7 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₇ ₓ ⁷C₃ = 1,763,580

Case V -

If 4 reggae song is selected

⇒All 6 songs selected from 7 blue, 7 disco, 5 pop,

Number of ways = ¹⁹C₆ ₓ ⁷C₄ = 949,620

So,

Total possible ways = 92,378+ 646,646+ 1,587,222+ 1,763,580+ 949,620

                               = 5,039,446

⇒Total possible ways = 5,039,446

Now,

Also the 10 songs selected can arranged themselves in 10! ways. ( because order of song played does not matter )

∴ we get

Different playlists possible = 10! × 5,039,446

                                          = 18287141644800

⇒Different playlists possible = 18287141644800

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Georgia needs to buy some cheese. An 8-ounce package of
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Answer:

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4 0
3 years ago
A bag contains 2 black balls, 4 yellow balls and 4 white balls. Event A is defined as drawing a white ball on the first draw and
arsen [322]

Answer: P(B|A)=\dfrac{4}{9}

Step-by-step explanation:

Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.

Event A is defined as drawing a white ball on the first draw.

Event B is defined as drawing a black ball on the second draw.

P(B|A) is expressed as the conditional probability of occurring B given that A.

i.e. it is the probability of happening B where A is already happended.

If a white ball is drawn at first, then the number of black ball(4) remains unchanged but the total number of balls (10) will become 9.

Probability=\dfrac{Number\ of \ favorable \ outcomes}{Total\ outcomes}

Then, P(B|A)=\dfrac{4}{9}

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Answer:F

Step-by-step explanation:

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3 years ago
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