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2 years ago

Explain why x2+81=0 does not have a solution

Mathematics

1 answer:

Stella [2.4K]2 years ago

6 0

Answer:

You have to take square root of -81

Step-by-step explanation:

It does not have a solution because you'd have to take the square root of -81

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Question 1 (Fill-In-The-Blank Worth 3 points)

goldenfox [79]

Non so che fare il primo a

5 0

1 year ago

-6x-6y =18 6x-3y=27 its supposed to be solving systems by elimination by adding or subracting, im really confused.

Lera25 [3.4K]

Answer:

y = -5

x = 2

Step-by-step explanation:

The computation is show below:

Given that

-6x - 6y = 18

6x - 3y = 27

Now if we solved both equation so

-9y = 45

y = -5

And, x is

-6x - 6(-5) = 18

-6x + 30 = 18

-6x = 18 - 30

-6x = -12

x = 2

3 0

2 years ago

Which digit could be the ten millions place that is less than 55,000,000 but greater than 25,000,000

Keith_Richards [23]

The answer is B hope this helped

8 0

3 years ago

A rectangular garden 6 meters wide has a diagonal measuring 10 meters. find the perimeter of the garden.

FromTheMoon [43]

The perimeter would be:
6+6+10+10
12+20
perimeter= 32
HOPE THIS HELPS YOU! ^_^

7 0

2 years ago

Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5

abruzzese [7]

Answer:

The answer is <em>1</em>.

Step-by-step explanation:

Given the expression:

$|z-6|-|z-5|,\ if\ z$

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

$y = f(x) = |x| =\left \{ {{x\ if\ x>0} \atop {-x\ if\ x$

i.e. value is x if x is positive

value is -x if x is negative

Here the given expression contains two absolute value functions:

$|z-6|$ and $|z-5|$

Using the definition of absolute value function as per above definition.

$|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z$

$|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z$

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression $|z-6|-|z-5|,\ if\ z$ will be equivalent to :

$-(z-6) - (-(z-5))\\\Rightarrow -z+6 +z-5 = \bold{1}$

So, the expression is equivalent to <em>1</em>.

6 0

3 years ago