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notka56 [123]
3 years ago
6

Write the equation of the line with a slope of 0 and containing the point (- 6, 5).

Mathematics
1 answer:
defon3 years ago
4 0
Y=mx+b
5=0(-6)+b
b=5
So equation
y=0x+5

Or

y=5
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Solve for x Write the smaller solution first, and the larger solution second.
posledela

Answer:

x= -18.16    x= -11.84

Step-by-step explanation:

(x+15)(x+15)=         x^2+30x+225-10=0

x^2+30x+215=0

a=1                      -30±√(30)²-4(1)(215)

b=30                   -----------------------------  

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4 years ago
I do be needing help tho ngl
Sliva [168]

Answer:

6^5

Step-by-step explanation:

( I put ^5 to show that I mean 6 with an exponent of 5) Hope this helped

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3 years ago
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3 years ago
Find the lateral surface area of this
Ksenya-84 [330]

Answer:

A=157.07\ cm^2

Step-by-step explanation:

Given that,

The radius of a cylinder, r = 5 cm

Height of the cylinder, h = 5 cm

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A=2\pi r h

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7 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

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y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
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