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AleksAgata [21]
3 years ago
14

409.0113 x230.2190931

Mathematics
1 answer:
dsp733 years ago
8 0

Answer:

9.416221055365203 x 10^4

Step-by-step explanation:

You just multiply

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Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va
Nat2105 [25]

Answer:

(a <em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>+</u></em><em><u>7</u></em><em><u>a</u></em><em><u>+</u></em><em><u>1</u></em><em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>÷</u></em><em><u>(</u></em><em><u>a</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em>

5 0
2 years ago
Tamora just made the last of her monthly payments on her loan. She had been making these payments for the past nine years. The l
Law Incorporation [45]
Answer : $3403.53

Detailed Solution: 
<span>principal was 10,675
interest rate was 4.75% per year compounded annually.
additional $939.25 was paid in service charges.
payment on the principal plus interest is shown below: 

pv = 10675
i = .0475/12 = .0039583333... per month.
n = 9 * 12 = 108 months.
fv = 0
pmt = 121.6635... per month
total finance charge would be (108 * 121.6635... + 939.25 - 10675).
that equals to 13139.66 + 939.25 - 10675 = 3403.91 
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4 0
3 years ago
Read 2 more answers
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
16 is what percent of 50?
vovikov84 [41]

Answer:

32

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the answer to 10-(8p+3)=9(2p-5) ?
aniked [119]

Use distribution.
10 - (8p + 3) = 10 - 8p - 3 = 7 - 8p
9(2p - 5) = 18p - 45

So...
-8p + 7 = 18p - 45
Subtract 7 from both sides
-8p = 18p - 52
Subtract 18p from both sides
-26p = 52
Divide both sides by -26.
p = -2

There's your answer :D

6 0
3 years ago
Read 2 more answers
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