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exis [7]
3 years ago
5

Problem kevin is 3 years older tan daniel. two years ago, kevin was 4 times as old as daniel. how old is daniel now?

Mathematics
1 answer:
Rashid [163]3 years ago
5 0
Let, the age of Daniel = x
Then, Age of Kevin = x + 3

Two years ago, (x + 1) = 4(x - 2)
x + 1 = 4x - 8
4x - x = 1 + 8
3x = 9
x = 9/3
x = 3

In short, Your Answer would be 3 Years

Hope this helps!
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22-10c

Step-by-step explanation:

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Viefleur [7K]
9(3+8x)
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In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
Troyanec [42]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

The rest of the question is the attached figure.

It is required to find the measure of the arc CD in degrees.

as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

∠APE and ∠BPE are supplementary angles

So, ∠APE + ∠BPE = 180°

∠BPE + 90 = 180°

∴ ∠BPE = 180 -90 = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

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Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

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Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

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Therefore, area of the given rhombus is 16 units².

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