Question

Evaluate (x^-2y^0)/(x^3y^-2) when x = 2 and y = 5. a. 25/2 b. 25/32 c. 50

Answer 1

Answer:

b. 25/32

Step-by-step explanation:

To evaluate the function

$f(x,y) = \frac{x^{-2}y^{0}}{x^{3}y^{-2}}$

When $x = 2, y = 5$ we replace x by 2 and y by 5 in the function. So:

$f(x,y) = \frac{x^{-2}y^{0}}{x^{3}y^{-2}}$

$f(2,5) = \frac{2^{-2}5^{0}}{2^{3}5^{-2}}$

Expressions wth negative exponents in the numerator go to the denominator with positive exponent. On the denominator goes to the numerator with positive exponent. So:

$f(2,5) = \frac{5^{2}5^{0}}{2^{3}2^{2}}$

$f(2,5) = \frac{5^{2}*1}{8*4} = \frac{25}{32}$

The correct answer is

b. 25/32

Answer 2

The answer is B. 25/32