Pls no time help me fast no links ill report u and no brainlist

Mathematics

1 answer:

Lena [83]3 years ago

7 0

Answer:

Step-by-step explanation:

Line segment Point Point Distance Proof

AB A(-3 , 4) B(2,4) 5 2 - (-3) = 2 +3 = 5

BC B(2,4) C(5,4) 3 5 - 2 = 3

CD C(5,4) D(5,-1) 5 4 -(-1) = 4 +1 = 5

DE D(5 , -1) E(5,-3) 2 -1 -(-3) = -1 +3 = 2

EF E(5, -3) F(-5,-3) 10 5 - (-5) = 5+5 = 10

You might be interested in

The volume of a cylinder is 4,019.2 cubic units. If the radius is 8 units, how tall is the cylinder?

AVprozaik [17]

We will be using the formula in looking for the volume of the cylinder which is

V = πr²h

where:

r = radius
h = height
V = volume

but in the problem V and r have values already:
r = 8
V = 4019.2

plug this in the volume equation:

V = πr²h
= 4019.2 = π* 8² * h
= 4019.2 = 64πh
= 4019.2 / 64π = h

so the answer is: h = 4019.2 /201.06193
= 19.99 is the height of the cylinder.

8 0

4 years ago

3. A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the l

sergeinik [125]

Answer: 3. The correct option is: A) 3.57 decibels.

6. The correct option is: B) $ln(\frac{x^2}{c^5})$ 

Step-by-step explanation:

3. Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.

So, $I_{0}= 100$ and $I= 44$

Using the formula $L= 10log(\frac{I}{I_{0}})$ , we will get.....

$L= 10log(\frac{44}{100})\\ \\ L= 10log(0.44)\\ \\ L= 10(-0.3565...)=-3.565...\approx -3.57$

(Rounded to the nearest hundredth)

So, the loudness would be reduced by 3.57 decibels.

6. Given expression is: $2ln(x) - 5ln(c)$

First applying the property $m*log(x)= log(x^m)$ , we will get.....

$ln(x^2)-ln(c^5)$

Now using the formula, $log(a)-log(b)= log(\frac{a}{b})$ , we will get....

$ln(x^2)-ln(c^5) = ln(\frac{x^2}{c^5})$

Thus, the answer as a single natural logarithm is $ln(\frac{x^2}{c^5})$

8 0

3 years ago

Find the solutions to x2 = 20.

Gemiola [76]

Answer:

Step-by-step explanation:

$x^2=20; \ => \ \left[\begin{array}{ccc}x=\sqrt{20} \\x=-\sqrt{20} \end{array} \ => \ \left[\begin{array}{ccc}x=2\sqrt{5} \\x=-2 \sqrt{5} \end{array}$