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zlopas [31]
4 years ago
11

25.0 g of a substance requires 117.4 Joules of energy to raise its temperature from 75.0 to 87.2 oC. What is the specific heat o

f the substance?
.054 J/g°C


.063 J/g°C


2.60 J/g°C


.385 J/g°C
Chemistry
2 answers:
denis-greek [22]4 years ago
5 0
0.385 is your answer
Sveta_85 [38]4 years ago
3 0

Answer:

0.385 J/g°C

Explanation:

c = q/mΔt

c = \frac{117.4J}{25g * 12.2 C} = 0.385 J/g°C

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raketka [301]

Answer:

Best  

Explanation:

5 0
3 years ago
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The pH of a solution is measured to be pH=10. What is true of this solution?
Marta_Voda [28]

Answer:

a. the solution is a base

Explanation:

The pH range is between 0 to 14.

A solution with a pH value between 0 and 6 is said to be acidic.

A solution with pH value at 7, is said to be neutral, e.g., distilled water.

A solution with pH value between 8 and 14 is a base.

Given pH = 10, a pH value of 10 falls between the base or alkali range of the indicator

8 0
4 years ago
A(n) _________is a material that contains only one type of atom.
joja [24]

Answer:

element

Explanation:

Elements are pure substances with only one kind of atom

7 0
4 years ago
Determine the mass of an object that has a volume of 88.6 ml and a density of 9.77 g/ml.
Nostrana [21]
Given:
The volume is V = 88 mL
Density, d = 9.77 g/mL

Because mass = volume *  density, therefore the mass of the object is
m = (88.6 \, mL)*(9.77 \,  \frac{g}{mL} )=865.62 \, g

Answer: The mass is 865.2 g  or  0.865 kg
4 0
4 years ago
What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?
FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0
2 years ago
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