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4 years ago

Why are the atoms of the group 8 elements unreactive??

Chemistry

1 answer:

anygoal [31]4 years ago

3 0

Answer:

because that is the last group the ones before it are more reactive im sorry if this not what you were looking for.

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The substance that waves travel though?

Sedaia [141]

C) medium.

The medium of a wave is any substance that carries the wave, or through which the wave travels.Ocean waves are carried by water, sound waves are carried by air, and. the seismic waves of an earthquake are carried by rock and soil.

5 0

3 years ago

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

3 0

3 years ago

Using today's current price of gold - $1838.80 per troy ounce, how much are 5.17x1017 atoms of gold worth? (Hint: You will have

Zepler [3.9K]

Answer:

0.010 $.

Explanation:

Hello!

In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:

$1,838.80\frac{\$}{try\ ounce} * \frac{1try\ ounce}{31.1g} = 59.1\frac{\$}{g}$

Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:

$m=5.17x10^{17}atomsAu*\frac{197.0gAu}{6.022x10^{23}atomsAu} \\\\m=1.69x10^{-4}g$

Thus, the price is:

$\$ = 59.1\frac{\$}{g}*1.69x10^{-4}g \\\\\$ =0.010\$$

Best regards!

7 0

3 years ago

read 30 points and a Brainliest no link or no robot I don't care what you do to help but it has to be right and all the answers

ziro4ka [17]

Answer:

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Explanation:

7 0

3 years ago

How to write equations and show units for the Total joules gained by water for the Pringle and the Total Joules per gram of food

Paraphin [41]

Answers:

1. 7500 J; 3800 J/g

Step-by-step explanation:

1. Joules gained by water

q = mcΔT

Data:

m = 100 g

C = 4.184 J·°C⁻¹g⁻¹

ΔT = 18 °C

Calculation:

q = 100 × 4.184 × 18 =7500 J

2. Joules per gram of Pringle

Energy gained by water = energy lost by Pringle

q = -mΔH

7500 J = -1.984 g × ΔH

ΔH = -7500 J/1.984 g = -3800 J/g

Pringles contain 3800 J of food energy per gram.

7 0

3 years ago

Why are the atoms of the group 8 elements unreactive??​

Why are the atoms of the group 8 elements unreactive??