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3 years ago

7

Why are the atoms of the group 8 elements unreactive??

1 answer:

anygoal [31]3 years ago

3 0

Answer:

because that is the last group the ones before it are more reactive im sorry if this not what you were looking for.

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Which of the following is an example of a reaction that you've seen in your everyday life ?

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3 years ago

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Milk of magnesia is a sparingly soluble suspension of magnesium hydroxide in water. it acts as an antacid by neutralizing hydroc

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The milk of magnesia is a suspension of magnesium hydroxide in water, which is a strong base that is used to neutralize excess stomach acid. The presence of stomach acid or hydrochloric acid (HCl) that is known to be a strong acid will react with the strong base and neutralization reaction occurs since conjugate partners produced negligible strength where the products are a salt and water.

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3 years ago

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2 years ago

Describe the features of a comet.

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2 years ago

In this activity, you will practice balancing overall redox reactions in acidic and basic solutions. To do this, you will apply

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Answer :

<u>Part A :</u> The given unbalanced redox reaction is,

$NH^+_4+MnO^-_4\rightarrow NO^-_3+Mn^{2+}$

Now we have to balance the given redox reaction in acidic medium by half reaction method.

1st half reaction : $8H^++MnO^-_4+5e^-\rightarrow Mn^{2+}+4H_2O$

2nd half reaction : $3H_2O+NH^+_4\rightarrow NO^-_3+10H^++8e^-$

For net balanced reaction, 1st half reaction is multiplying by 8 and 2nd half reaction is multiplying by 5

The net balanced redox reaction is,

$8MnO^-_4+14H^++5NH^+_4\rightarrow 8Mn^{2+}+17H_2O+5NO^-_3$

<u>Part B :</u> The given unbalanced redox reaction is,

$Cr(OH)_3+ClO^-_3\rightarrow CrO^{2-}_4+Cl^-$

Now we have to balance the given redox reaction in basic medium by half reaction method.

1st half reaction : $Cr(OH)_3+H_2O+5OH^-\rightarrow CrO^{2-}_4+5H_2O+3e^-$

2nd half reaction : $ClO^-_3+6H_2O+6e^-\rightarrow Cl^-+3H_2O+6OH^-$

For net balanced reaction, 1st half reaction is multiplying by 2.

The net balanced redox reaction is,

$2Cr(OH)_3+ClO^-_3+4OH^-\rightarrow 2CrO^{2-}_4+Cl^-+5H_2O$

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3 years ago