Required moles of CH₃COONa.3H₂O = Molarity x Volume of solution in L
= 0.100 M x (100.0 mL)
= 0.100 M x 0.100 L
= 0.01 mol
Required mass of CH₃COONa.3H₂O = Required moles x Molar mass
= 0.01 mol x (136.08 g / mol) = 1.3608 g
It will be easier to answer if you show the choices.
Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
![Rate = k[AB]^2](https://tex.z-dn.net/?f=Rate%20%3D%20k%5BAB%5D%5E2)
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
Where,
is the initial concentration = 1.50 mol/L
is the final concentration = 1/3 of initial concentration =
= 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-


<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>
B. Non- renewable resources are used up faster than it is made.