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-Dominant- [34]

2 years ago

5

There are many different ways to classify matter, but one way is to use only two categories for all matter. All matter can be cl

assified as either
a. liquids or gases.
b. atoms or molecules.
c. elements or compounds.
d. mixtures or substances.

1 answer:

Strike441 [17]2 years ago

3 0

I would put down C. elements or compounds

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The [α] of pure quinine, an antimalarial drug, is −165. If a solution contains 86% quinine and 14% of its enantiomer (ee = 72%),

ratelena [41]

Answer : The [α] for the solution is, -118.8

Explanation :

Enantiomeric excess : It is defined as the difference between the percentage major enantiomer and the percentage minor enantiomer.

Mathematically,

$\%\text{ Enantiomer excess}=\%\text{ Major enantiomer}-\%\text{ Minor enantiomer}$

Given:

% major enantiomer = 86 %

% minor enantiomer = 14 %

Putting values in above equation, we get:

$\%\text{ Enantiomer excess}=86\%-14\%=72\%$

$\text{ Enantiomer excess}=\frac{72}{100}=0.72$

Now we have to calculate the [α] for the solution.

$[\alpha]=\text{Enantiomer excess}\times [\alpha]_{Pure}$

$[\alpha]=0.72\times -165$

$[\alpha]=-118.8$

Thus, the [α] for the solution is, -118.8

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2 years ago

Which of the following is similar among all living organisms on Earth?

statuscvo [17]

A. cellular function

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mel-nik [20]

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GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g

JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

$H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ$

Divide the equation by 2.

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

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Define electronegativity. Where on the periodic table is the highest? Explain why this is the case.

geniusboy [140]

Answer:

Explanation:

Electronegativity is a measure of the ability of an atom to attract the electrons when the atom is part of a compound. Electronegativity values generally increase from left to right across the periodic table. The highest electronegativity value is for fluorine.

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2 years ago