f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
Answer:
The number of palindromes is
when n is even and
when n is odd
Step-by-step explanation:
From the question we are told that
The length of the string is 
Generally palindrome is evaluated by considering the first part of a string
When the the length of the string is an even number then
it means that the first part of the string is 
Hence the number of bit strings of length n that are palindromes is evaluated as
But When the the length of the string is an odd number then
it means that the first part of the string is 
Hence the number of bit strings of length n that are palindromes is evaluated as
Generally each bit could be either 0 or 1
Hence the number of palindromes is
when n is even and
when n is odd
Please retype this fraction. If by "---" you mean "subtraction," type 3/7-1/3.
Let's assume that the problem is as follows: (3/7-1/3)(2/3)-1/7;
first, find the LCD of 3/7 and 1/3 and then combine 3/7 and -1/3).
second, multiply your result by (2/3).
third, subtract 1/7 from your result.
If, however, your "---" and "-----" mean "division, then the above is all wrong.
If that's the case, then please retype your whole question.
You could express "the quotient of 2/3 and 1/6" as follows:
2
----
3
------------------------
1
-----
6
Is that what you meant?
Sorry to be picky, but it's very important that you express math properly.
Plug 50 into y and find x.
5x + 10 (50) = 800
5x + 500 = 800
5x = 800 - 500
5x = 300
x = 300 ÷ 5
x = 60
Multiply the price by (1 + sales tax).
85 x (1+0.07)
85 x 1.07 = 90.95
He will pay $90.95
