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Ronch [10]
3 years ago
14

X+y=2 8x+3y=-19 substitution

Mathematics
2 answers:
MrRa [10]3 years ago
5 0

Answer:

Input:

f(x, y) = x^2 - y^2

Geometric figure:

hyperbolic paraboloid

3D plot:

3D plot

Contour plot:

Contour plot

Alternate form:

f(x, y) = (x - y) (x + y)

Alternate form assuming x and y are positive:

x^2 = f(x, y) + y^2

Properties as a function:

Domain

R^2

Range

R (all real numbers)

Parity

even

Partial derivatives:

d/dx(x^2 - y^2) = 2 x

d/dy(x^2 - y^2) = -2 y

Indefinite integral assuming all variables are real:

integral(x^2 - y^2) dx = x^3/3 - x y^2 + constant

padilas [110]3 years ago
4 0

Answer:

{x,y}={−5,−7}

Explain:

// Solve equation [2] for the variable  y [2]    3y = 7x + 14 [2]    y = 7x/3 + 14/3 // Plug this in for variable  y  in equation [1] [1]    8x - 3•(7x/3+14/3) = -19 [1]    x = -5 // Solve equation [1] for the variable  x [1]    x = - 5 // By now we know this much : x = -5 y = 7x/3+14/3 // Use the  x  value to solve for  y y = (7/3)(-5)+14/3 = -7 Solution : {x,y} = {-5,-7}

Hoped I helped

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Step-by-step explanation:

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4 0
3 years ago
Can someone help me with these three questions?
N76 [4]

Answer:

1. =

2. <

3. <

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1 is equal to because once you put a 0 behind the 2.1 they are both the same.

2.10

2.1    <add 0 as space holder

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2 years ago
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To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!

\boxed{ \sf \: area \: of \: square =side ^{2}  }

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\rm \implies \: area = 3 ^{2}

\rm \implies9

<em>Thus, The area of 1st square is 9m²...</em>

  • The area of second square will be also 9m², because the sides of both squares are equal.

<h3>Now area of the reactangle⤵️</h3>

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\tt \dashrightarrow \: area = 30m ^{2}

<em>Thus, The area of rectangle is 30m²....</em>

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