Answer:
<h3>
Step-by-step explanation:</h3>
The z-value is computed from ...
... z = (x -µ)/σ
... z = (184 -206)/10 = -2.2 . . . . for $184
... z = (200 -206)/10 = -0.6 . . . . for $200
You can look up these values in a normal distribution table, or you can use an appropriate calculator to find the corresponding percentiles.
... -2.2 corresponds to the 1.390 percentile. (That amount of area is below -2.2 standard deviations from the mean.)
... -0.6 corresponds to the 27.425 percentile.
Subtracting the two percentages gives the percentage of expenses between $184 and $200. That number is 26.035% ≈ 26%.
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<em>Comment on the calculator display</em>
The difference that got cut off from the display in the attachment is ...
... 0.2603496703
The <em>normalcdf( )</em> function requires a lower limit. Using -8 standard deviations is effectively equivalent to -∞ for this purpose, as any lower number has no effect on the least-significant digits of the result.
Y= 3x + 3. Use rise (how many it goes up or down) and divide it by run (how many it goes left or right) that number is your slope (aka M/ the number that goes with x. The number without the x attached is just where the line crosses the y axis
Answer:
12
Step-by-step explanation:
all you have to do is simply to find the LCM of the denominators
the LCM of each denominator would be 12
Area of a square with side s is

In your question, the side or s is:

And so the area of a square with that side length would be:

And using this formula:

We get that the area is:

And simplifying that we get the final answer as:
![\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20-7x-2y%3D4%5Cimplies%20-2y%3D7x%2B4%5Cimplies%20y%3D%5Ccfrac%7B7x%2B4%7D%7B-2%7D%5Cimplies%20y%3D%5Ccfrac%7B7x%7D%7B-2%7D%2B%5Ccfrac%7B4%7D%7B-2%7D%20%5C%5C%5C%5C%5C%5C%20y%3D%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B7%7D%7B2%7D%7D%20x-2%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.