Question

What is the area of a square with a side of 8x^7 y^3

Answer 1

Area of a square with side s is $\sf{s^2}$

In your question, the side or s is: $\sf{8x^7y^3}$

And so the area of a square with that side length would be:

$\sf{(8x^7y^3)^2}$

And using this formula: $\sf{(a^b)^c =a^{b\times c}}$

We get that the area is:

$\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}$

And simplifying that we get the final answer as:

$\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}$