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olga2289 [7]
3 years ago
11

What is the area of a square with a side of 8x^7 y^3

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0
Area of a square with side s is \sf{s^2}

In your question, the side or s is: \sf{8x^7y^3}

And so the area of a square with that side length would be:

\sf{(8x^7y^3)^2}

And using this formula: \sf{(a^b)^c =a^{b\times c}}

We get that the area is:

\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}

And simplifying that we get the final answer as:

\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}
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