Given:
Q = 0.0764 kJ = 764 J, heat input
W = -830 J, useful work done
From the 1st Law of Thermodynamics, the change in internal energy is
δE = Q - W
= 764 - (-830)
= 1594 J = 1.594 kJ
Answer: 1.59 kJ (two sig. fig.)
Answer:
Consider the right triangle below.
5x - 3
2x + 7
X + 4
If the perimeter is 40 units, find the value of x and the area
of the triangle.
Step-by-step explanation: